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Last updated on September 27, 2025
We use the derivative of cos²(2x) to understand how this function changes in response to a slight change in x. Derivatives help us calculate profit or loss in real-life situations. We will now discuss the derivative of cos²(2x) in detail.
We now understand the derivative of cos²(2x). It is commonly represented as d/dx (cos²(2x)) or (cos²(2x))', and its value is -4cos(2x)sin(2x). The function cos²(2x) has a clearly defined derivative, indicating it is differentiable within its domain.
The key concepts are mentioned below:
Cosine Function: (cos²(2x) = (cos(2x))²).
Chain Rule: Rule for differentiating composite functions like cos²(2x).
Product Rule: A rule used when differentiating products of functions.
The derivative of cos²(2x) can be denoted as d/dx (cos²(2x)) or (cos²(2x))'.The formula we use to differentiate cos²(2x) is: d/dx (cos²(2x)) = -4cos(2x)sin(2x)
The formula applies to all x where cos(2x) ≠ 0.
We can derive the derivative of cos²(2x) using proofs. To show this, we will use trigonometric identities along with the rules of differentiation.
There are several methods we use to prove this, such as:
We will now demonstrate that the differentiation of cos²(2x) results in -4cos(2x)sin(2x) using the above-mentioned methods:
The derivative of cos²(2x) can be proved using the First Principle, which expresses the derivative as the limit of the difference quotient. To find the derivative of cos²(2x) using the first principle, we will consider f(x) = cos²(2x). Its derivative can be expressed as the following limit. f'(x) = limₕ→₀ [f(x + h) - f(x)] / h … (1) Given that f(x) = cos²(2x), we write f(x + h) = cos²(2(x + h)). Substituting these into equation (1), f'(x) = limₕ→₀ [cos²(2(x + h)) - cos²(2x)] / h Using trigonometric identities and simplifying, we use cos²A - cos²B = (cos(A + B))(cos(A - B)) f'(x) = limₕ→₀ [(cos(2x + 2h)cos(2x - 2h))] / h Upon further simplification and using limits, f'(x) = -4cos(2x)sin(2x)
To prove the differentiation of cos²(2x) using the chain rule, We use the formula: cos²(2x) = (cos(2x))² Let u = cos(2x) Then, cos²(2x) = u² Using the chain rule, d/dx (u²) = 2u (du/dx) Here, du/dx = -2sin(2x) Substitute back, d/dx (cos²(2x)) = 2cos(2x)(-2sin(2x)) = -4cos(2x)sin(2x)
We will now prove the derivative of cos²(2x) using the product rule. The step-by-step process is demonstrated below: Here, we use the formula, cos²(2x) = cos(2x) · cos(2x) Given that, u = cos(2x) and v = cos(2x) Using the product rule formula: d/dx [u.v] = u'.v + u.v' u' = d/dx (cos(2x)) = -2sin(2x) v' = d/dx (cos(2x)) = -2sin(2x) Using the product rule formula: d/dx (cos²(2x)) = u'.v + u.v' = (-2sin(2x))cos(2x) + cos(2x)(-2sin(2x)) = -4cos(2x)sin(2x)
When a function is differentiated several times, the derivatives obtained are referred to as higher-order derivatives. Higher-order derivatives can be a little tricky. To understand them better, think of a car where the speed changes (first derivative) and the rate at which the speed changes (second derivative) also changes. Higher-order derivatives make it easier to understand functions like cos²(2x).
For the first derivative of a function, we write f′(x), which indicates how the function changes or its slope at a certain point. The second derivative is derived from the first derivative, which is denoted using f′′(x). Similarly, the third derivative, f′′′(x) is the result of the second derivative and this pattern continues.
For the nth Derivative of cos²(2x), we generally use fⁿ(x) for the nth derivative of a function f(x), which tells us the change in the rate of change (continuing for higher-order derivatives).
When x equals π/4, the derivative is -4cos(π/2)sin(π/2) = 0 because sin(π/2) = 0.
When x equals 0, the derivative of cos²(2x) = -4cos(0)sin(0) = 0.
Students frequently make mistakes when differentiating cos²(2x). These mistakes can be resolved by understanding the proper solutions. Here are a few common mistakes and ways to solve them:
Calculate the derivative of (cos²(2x) · sin(2x))
Here, we have f(x) = cos²(2x) · sin(2x). Using the product rule, f'(x) = u′v + uv′ In the given equation, u = cos²(2x) and v = sin(2x). Let’s differentiate each term, u′ = d/dx (cos²(2x)) = -4cos(2x)sin(2x) v′ = d/dx (sin(2x)) = 2cos(2x) Substituting into the given equation, f'(x) = (-4cos(2x)sin(2x))(sin(2x)) + (cos²(2x))(2cos(2x)) Let’s simplify terms to get the final answer, f'(x) = -4cos(2x)sin²(2x) + 2cos³(2x) Thus, the derivative of the specified function is -4cos(2x)sin²(2x) + 2cos³(2x).
We find the derivative of the given function by dividing the function into two parts.
The first step is finding its derivative and then combining them using the product rule to get the final result.
A company's revenue is modeled by the function y = cos²(2x), where y represents revenue in thousands of dollars at time x in months. If x = 3 months, measure the rate of change of revenue.
We have y = cos²(2x) (revenue model)...(1) Now, we will differentiate the equation (1) Take the derivative of cos²(2x): dy/dx = -4cos(2x)sin(2x) Given x = 3 (substitute this into the derivative) dy/dx = -4cos(6)sin(6) Using a calculator, find the values of cos(6) and sin(6) and compute. Hence, we get the rate of change of revenue at x = 3 months.
We find the rate of change of revenue at x = 3 months by calculating the derivative at that point, which shows the change in revenue over time.
Derive the second derivative of the function y = cos²(2x).
The first step is to find the first derivative, dy/dx = -4cos(2x)sin(2x)...(1) Now we will differentiate equation (1) to get the second derivative: d²y/dx² = d/dx [-4cos(2x)sin(2x)] Here we use the product rule, d²y/dx² = -4[d/dx (cos(2x)sin(2x))] = -4[(-2sin(2x)sin(2x) + 2cos²(2x))] = 8sin²(2x) - 8cos²(2x) Therefore, the second derivative of the function y = cos²(2x) is 8sin²(2x) - 8cos²(2x).
We use the step-by-step process, where we start with the first derivative.
Using the product rule, we differentiate the expression and then simplify the terms to find the final answer.
Prove: d/dx (cos⁴(2x)) = -8cos³(2x)sin(2x).
Let’s start using the chain rule: Consider y = cos⁴(2x) = [cos(2x)]⁴ To differentiate, we use the chain rule: dy/dx = 4[cos(2x)]³ · d/dx [cos(2x)] Since the derivative of cos(2x) is -2sin(2x), dy/dx = 4[cos(2x)]³ · (-2sin(2x)) = -8cos³(2x)sin(2x) Hence proved.
In this step-by-step process, we used the chain rule to differentiate the equation.
Then, we replace cos(2x) with its derivative.
As a final step, we substitute y = cos⁴(2x) to derive the equation.
Solve: d/dx (cos²(2x)/x)
To differentiate the function, we use the quotient rule: d/dx (cos²(2x)/x) = (d/dx (cos²(2x)) · x - cos²(2x) · d/dx(x))/x² We will substitute d/dx (cos²(2x)) = -4cos(2x)sin(2x) and d/dx(x) = 1 = (-4cos(2x)sin(2x) · x - cos²(2x) · 1)/x² = (-4xcos(2x)sin(2x) - cos²(2x))/x² Therefore, d/dx (cos²(2x)/x) = (-4xcos(2x)sin(2x) - cos²(2x))/x²
In this process, we differentiate the given function using the quotient rule.
As a final step, we simplify the equation to obtain the final result.
Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
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